思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
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Valentine's Dinner
«Били в одно место». Российский газовоз уничтожен украинскими дронами в Средиземном море. Что известно об атаке и судьбе моряков14:20